The question off which I am basing my question assumes that [Pt(Cl)(Br)(PPh3)2] can exist in either the square-planar or tetrahedral geometry. If one would use Pt-195 NMR spectroscopy how would the spectra of the possible molecules differ from each other? The effect of the Cl and Br can be disregarded.
For the square planar geometry, either the cis or trans isomer is possible. I am assuming that you won't be able to distinguish between the square planar trans molecule and the tetrahedral molecule since the PPh3 ligands in each molecule are equivalent. The Pt-195 NMR spectra for these two orientations will thus be the same, a single triplet.
Will the square planar cis molecule also produce the same spectrum or will there be second-order coupling present since the PPh3 ligands are non-equivalent? How would the Pt-195 NMR spectra then look for the cis isomer? Thank you in advance for anyone willing to help!