Think the Maxwell's equations.
Assume here a big assumption that a neutron has a pure imaginary electric charge.
From the Maxwell's equations, it can be anticipated that such a neutron produces pure imaginary electromagnetic fields around itself.
The present electromagnetism teaches us that the energy of an electromagnetic field is given by the sum of E^2+B^2.
So that for the pure imagenary electromagnetic fields, the energy becomes negative.
On the other hand, protons each of which has pure real electric charge repel each other.
This repulsion can be considered as a result of Maxwell's stress, which in turn, can be related to the electromagnetic energy around the protons. This energy is positive since the proton's electric charge is pure real.
If we combine appropriate numbers of protons and neutrons, then the proton's repulsive stress energy might be cancelled out because proton's energy and neutron's energy counteract as shown in the above equations (1) and (2). As a result each proton does not exert repulsive force on each other anymore. Therefore elemental nucleus can continue to exist stably only if an appropriate number of neutrons participate to constitute the nucleus.
How do you like this idea?
A Physical Dreamer
June 13, 2012
Another idea has occured to me.
How about assigning complex number charge to electron, proton, neutron?
The idea is very simple.
Let the charge of an electron be -q.
Let the charge of proton be +q+ir.
Let the charge of neutron be +ir.
where r is the magnitude of the assumed residual imaginary charge.
In this scheme, the charge of the electron is pure real number, the one of proton the complex number and the one of the neutron the pure imaginary number.
Now let us proceed to decide whether the charge product, especially the real part of the product becomes negative or positive.
For electron vs electron: Re(-q)(-q)=Re(+q^2)=+q^2, so that the force is repulsive.
For proton vs proton: Re(q+ir)(q+ir)=Re(q^2+2iqr-r^2)=q^2-r^2, so that the sign of the force is dependent on the relative magnitude of q and r.
For neutron vs neutron: Re(ir)(ir)=Re(-r^2)=-r^2, so that the force is attractive.
For electron vs proton: Re(-q)(+q+ir)=Re(-q^2-iqr)=-q^2, so that the force is attractive.
For electron vs neutron: Re(-q)(ir)=Re(-iqr)=0, so that the force is zero.
For proton vs neutron: Re(+q+ir)(+ir)=Re(iqr-r^2)=-r^2, so that the force is attractive.
To sum up, the above scheme works well to hold the nuclear system stably and at the same time the atomic system as well.
By the introduction of the imaginary compornent ir, the inter-proton repulsive force can be diminished or vanished. And the force between the neutrons is attractive. And the force between the proton and neutron is also attractive. When all these conditions hold, the nucleus comprising plurality of proton and neutron can stably exist. The nucleus will not explode.
And in addition, the neutrons do not assert any force on the electrons, and the force between the electron and the proton is the same as before.
How do you like this idea?
Are there remaining any difficulties still?
Further another idea has occured to me.
Why do we treat electric charge as absolute constant?
How about a possibility of our being deceived by a superficial constancy of them?
How about this idea?
Charge Q=a complex function of time like q exp( i omega t) (1)
Then a product between charges Q1 and Q2 may be written like
Q1Q2=q1q2 exp( i (omega1+omega2) t ) (2)
This charge product could cause an esoteric behavior, or could explain the strange nuclear binding, depending the angular frequancies omega1 and omega2. The omega's may be huge numbers.
Of course, other wild functional forms are possible to think. The doors are open to variuous directions and possibilities.
A Pithecantropus Japonicus who does not know the modern science yet
March 16, 2013